Задание
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Найти числовое значение алгебраического выражения:
1) (2mn*(n + k)) / (n - k) при m = k = 1/3, n = 1/2
2) ((3p + l) * 2p) / (p – l) + 1/3 при p = 1/3, l = 1
1) (2mn*(n + k)) / (n - k) при m = k = 1/3, n = 1/2
2) ((3p + l) * 2p) / (p – l) + 1/3 при p = 1/3, l = 1
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1) (2mn*(n + k)) / (n - k)
при m = k = 1/3, n = 1/2
(2 * 1/3 * 1/2 * (1/2 + 1/3)) / (1/2 – 1/3) = (1/3 * 5/6) / (1/6) = 1/3 * 5/6 * 6 = 5/3
2) ((3p + l) * 2p) / (p – l) + 1/3
при p = 1/3, l = 1
((3 * 1/3 + 1) * 2/3) / (1/3 – 1) + 1/3 = (4/3) / (-2/3) + 1/3 = -2 + 1/3 = - 5/3
при m = k = 1/3, n = 1/2
(2 * 1/3 * 1/2 * (1/2 + 1/3)) / (1/2 – 1/3) = (1/3 * 5/6) / (1/6) = 1/3 * 5/6 * 6 = 5/3
2) ((3p + l) * 2p) / (p – l) + 1/3
при p = 1/3, l = 1
((3 * 1/3 + 1) * 2/3) / (1/3 – 1) + 1/3 = (4/3) / (-2/3) + 1/3 = -2 + 1/3 = - 5/3
1) (2mn*(n + k)) / (n - k)
при m = k = 1/3, n = 1/2
(2 * 1/3 * 1/2 * (1/2 + 1/3)) / (1/2 – 1/3) = (1/3 * 5/6) / (1/6) = 1/3 * 5/6 * 6 = 5/3
2) ((3p + l) * 2p) / (p – l) + 1/3
при p = 1/3, l = 1
((3 * 1/3 + 1) * 2/3) / (1/3 – 1) + 1/3 = (4/3) / (-2/3) + 1/3 = -2 + 1/3 = - 5/3
при m = k = 1/3, n = 1/2
(2 * 1/3 * 1/2 * (1/2 + 1/3)) / (1/2 – 1/3) = (1/3 * 5/6) / (1/6) = 1/3 * 5/6 * 6 = 5/3
2) ((3p + l) * 2p) / (p – l) + 1/3
при p = 1/3, l = 1
((3 * 1/3 + 1) * 2/3) / (1/3 – 1) + 1/3 = (4/3) / (-2/3) + 1/3 = -2 + 1/3 = - 5/3